12x^2+240x-900=0

Solution for 12x^2+240x-900=0 equation:

12x^2+240x-900=0

a = 12; b = 240; c = -900;
Δ = b2-4ac
Δ = 2402-4·12·(-900)
Δ = 100800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{100800}=\sqrt{14400*7}=\sqrt{14400}*\sqrt{7}=120\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-120\sqrt{7}}{2*12}=\frac{-240-120\sqrt{7}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+120\sqrt{7}}{2*12}=\frac{-240+120\sqrt{7}}{24}
$